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Sample problem 1:
(2200H) = 04
(2201H) = 34H
(2202H) = A9H
(2203H) = 78H
(2204H) =56H
Result = (2202H) = A9H
Source program :
- LDA 2200H
- MOV C, A : Initialize counter
- XRA A : Maximum = Minimum possible value = 0
- LXI H, 2201H : Initialize pointer
- BACK: CMP M : Is number> maximum
- JNC SKIP : Yes, replace maximum
- MOV A, M
- SKIP: INX H
- DCR C
- JNZ BACK
- STA 2300H : Store maximum number
- HLT : Terminate program execution
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