65,535
It is 10 crossovers.
12
The maximum number of intersection points formed by 4 lines occurs when no two lines are parallel and no three lines are concurrent (i.e., they do not all meet at a single point). In this case, each pair of lines can intersect at a unique point. The number of ways to choose 2 lines from 4 is given by the combination formula ( \binom{n}{2} ), so for 4 lines, the maximum number of intersection points is ( \binom{4}{2} = 6 ).
depends on the position of the points if points are collinear, we have just only one line, the minimum number. If points are in different position (if any of the two points are not collinear) we have 21 lines (7C2), the maximum number of lines.
It is 10 crossovers.
Six (6)
22
16
The maximum number of parts a circle can be divided into by using ( n ) straight lines is given by the formula ( \frac{n(n + 1)}{2} + 1 ). For 100 straight lines, this calculation becomes ( \frac{100(100 + 1)}{2} + 1 = 5051 ). Thus, with 100 straight lines, the maximum number of parts a circle can be divided into is 5051.
With n lines, the maximum number is n*(n-1)/2. The minimum is 0.
The maximum number of areas that can be formed by drawing three straight lines through a circle is seven. This occurs when the lines are arranged such that no two lines are parallel, and no three lines intersect at a single point. Each additional line can intersect all previous lines, increasing the number of distinct regions created within the circle.
11