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The low order address bus and the data bus on an 8085 are separated using an 8-bit latch that is strobed using ALE during the first T-cycle of a bus cycle. The bus represents valid address information on the falling edge of ALE. Soon thereafter, somewhat less than one half clock cycle, the bus changes meaning to become the data bus, and will float for a read or become output data for a write.
The high order address bus is already separated, and does not need to be latched.
the 8085 microprocessor is a 8-bit microprocessor and these are bidirectional but the address lines are unidirectional.these address lines are used to address the location of the instruction in memory .these data lines are used to transfer data between processor and peripheral devices. when the address of the instruction will be recognized by the address lines the data will be send to the processor therefore the 16 address lines are not act as a data lines in 8085
HL is a register pair used to store 16 bit of data in 8085 microprocessor.
microprocessor 8085 is basic 8 bit microprocessor by Intel Corp. it has 64Kb memory and 16 address buses and 8 data buses it has 40 pin ic. 8 address and 8 data buses are multiplexed with each other for reducing the total number of pins from the microprocessor 8085 . it require 5MHz clock frequency for operation. only a crystal which connected easily across two pins of microprocessor can provide this clock.
It is register addressing mode, as it moves the content of HL to PC which is data and not address.
You add the three numbers, then divide the result by 3.
HL is a register pair that is used to store 16-bit data in 8085 Microprocessor
The 8085 is an 8 bit microprocessor. It cannot directly handle 32 bit data. That said, it is possible to write a routine that can handle 32 bit data, just 8 bits at a time.
The Intel 8085 is an 8 bit microprocessor created in 1977.The Intel 8086 is a 16 bit microprocessor created in 1978. The 8086 was the first chip to start the x86 architecture family.8085 contains 16-bit address bus and 8-bit data bus8086 contains 20-bit address bus and 16-bit data bus..In 8085 the clock speed is 3MHZwhere as in 8086 the clock speed is 5MHZ.there are two differences btw 8085&80861. 8086 has 6 byte queue but 8085 has 4 byte queue2. 8086 has 16 bit data bus where as 8085 has 8 bit data bus
In the 8085 microprocessor, the instruction LHLD stands for "Load H and L Direct." It is used to load the registers H and L with a 16-bit data stored at a specified memory address. The instruction takes a 16-bit address as its operand, and the content of that address and the next sequential address are loaded into the L and H registers, respectively. This operation is useful for retrieving data from memory into these registers for further processing.
The address bus is unidirectional becos address information is always given by microprocessor to i/o devices. The data bus is bidirectional bcos it takes the data from other devices & also give the data to other i/o devices
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
The 8085 has a 16 bit address bus. As such, it can access 216, or 65,536 bytes. System design, of course, will place limits on that, as you need to share this space with code, data, and stack.