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What is the largest size memory card for playstation 3?
There are no memory cards for the Playstation 3. Data is saved to the hard drive.
How is a given unit of data located in a memory?
A given unit of data in memory is located using its unique address, which serves as an identifier for that specific location. Memory is typically organized in a linear, sequential manner, allowing the system to access data by calculating the address based on the starting point and the size of the data unit. The memory address is usually represented in binary format, and the memory management unit (MMU) translates these addresses for efficient data retrieval. This process allows the CPU to quickly locate and manipulate data stored in RAM or other memory types.
What is size of data bus and the address bus in 8085?
A 16-bit uP operates on instructions and data in 16-bit quantities. Therefore the databus is 16-bits. A 16-bit uP may also operate on larger quantities of data, however multiple CPU registers must be concatenated in order to maintain the data element in the uP register space. The data is always delivered to the processor 16 bits at a time. The amount of memory which it can address is a separate issue---the address bus size is totally distinct from the data bus size. The data bus determines how much memory may be delivered to the uP per cycle. The address bus size determines how much physical memory may actually be accessed by the uP. Therefore it is variable depending on how much memory is available. Typical systems today have 32-bit address busses which limit addressable memory to 4Gigabytes. (2^32) = 4G.
How memory space is occupied by union variables in C programming language?
A union is an aggregate of members that share the same memory address. The size of a union is determined by the largest member.
What is the largest size memory card for laptops?
The largest RAM upgrade is 4GB on a single stick of memory.
How will the memory be allocated in unions when 2 data types say int n float are declared?
A "Union" is a data type whose size will be determined by the member with largest size inside the union. So: union MyUnion{ int MyInteger; float MyFloat; }; MyUnion's size will be MyFloat's size, because that float is the largest sized member.
Why 4 bit address bus is grounded?
The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
Suppose that a machine has 48-bit virtual addresses, what are the implications of this address size on memory management and system performance?
With 48-bit virtual addresses, the machine can address up to 256 terabytes of memory. This large address space allows for more efficient memory management, as it can accommodate a greater number of processes and data. However, the increased address size may also lead to higher memory overhead and potential performance issues due to the larger memory footprint. Overall, the implications of a 48-bit address size on memory management and system performance include improved scalability but potential trade-offs in memory efficiency and performance.
How can a technician guarantee that the memory is correctly aligned?
A technician can guarantee memory alignment by ensuring that memory addresses start at an address divisible by the memory size being accessed. This alignment is crucial for efficient memory access and data integrity. Using data types that enforce alignment, such as in some programming languages, helps maintain correct alignment.
What is the largest memory card?
Android currently supports Micro SD cards of up to 32GB in size.
What is the largest size of memory card available by MaddCatz?
Currently the largest memory card Mad Catz produces for any of the systems is 64MB.
Which is faster- Reading word size data whose starting address is at even or at odd address of memory in 8086?
In the 8086 microprocessor, reading word-sized data is generally faster from an even address than from an odd address. This is because the 8086 architecture is designed to access memory in 16-bit (word) chunks, and even addresses allow the processor to retrieve data more efficiently, aligning with its access patterns. When a word is at an odd address, the processor must perform an additional cycle to fetch the data, resulting in slower access times.
