In the 8085 microprocessor, the MOV instruction copies data between two registers, or between a register and memory. The MVI instruction differs only in that the source data is contained in the byte immediately following the opcode byte.
Suppose you want to add 11 and 12.instruction are : mvi a,11h mvi b ,12h mov d,b add b
No, not at all this instruction MOV can not be used for immediate data transfer. You will need to use command MVI Rd, 8 Bit Data for immediate data transfer.
Data transfer in the 8085 microprocessor can be done with the help of several instructions like the MOV,MVI,OUT and IN . Lets say, we want to move the contents of a register R1 to register R2, then we could use the instruction MOV R2,R1 ; and so on...
Lda 8500 mov c,a cpi 02h jz l1 cpi 01h jz l1 mvi e,01h mvi h,00 mvi b,02h l4: mvi d,00 mov a,c l2: sub b inr d cmp b jnc l2 cmp e jz l3 jnc l3 inr h l3:inr b dcr d jnz l4 mov a,h cmp e jz l5 jnc l5 mov a,01 sta 8501 hlt l5: mov a,0e sta 8501 hlt
Lxi h,xx50 mov a,m inx h mov b,m mvi ,ffh inr c sub b jnc xx08 add b inx h mov m,c inx h mov m,a hlt
Mvi c lda 4150h mov b,a lda 4151 sub b jnc loop cma inr a inr c sta 4152 mov a,c sta 4153 hlt
loop: mvi c,59 dcr c mov a,c daa movc,a jnz loop end
the purpose of mvi is to 8 bit data immidiatly to the register or memory example mvi b,05h will move 05h to register b
4000 lda 50003a,00,504003 mvi b 0206,024005 mov c,a4f4006 mov d,a574007loop2mvi a 003e,004009loop1add d82400a dcr c0d400b jnz loop1c2,09,40400e mov c,a4f400f dcr b054010 jnz loop2c2,07,404013 mov a,c794014 sta 500532,05,504017 hlt76 enjoy dear friends :) by abin james nellanikattu
Xra a [(making the accumulator zero) or you can also write mvi a,00 but will probably take more t-states] lxi h dooo(can be any other address)give the range(n) mov b,m mvi c,01 again: add c inr c dcr b jnz again [loop] inx h mov m,a hlt
;A assembly program to reverse a number. jmp start ;data ;code start: nop mvi e,0f0h; ;no. to be reversed mvi d,00h; ;result mvi c,11h; ;masking bits mvi a,11h; ;to store the current mask mvi h,04h; ;counter mvi b,01h; rev: ana e; ;using the mask jz end; mov l,a; ;temp storage for storing the bits ani 0fh; ;storing the lsb's mov a,l; mov l,b; shift: rrc; dcr l; jnz shift; ora d; mov d,a; end: mov a,c; rlc; mov c,a; inr b; inr b; dcr h; jnz rev; hlt
What is the different between LXI and LHLD in 8085?LHLD 2050 Means..copy content of 2050 and 2051 to HL pairif2050 -> 90H2051->5AHLHLD 2050 implies..L -> 90HH -> 5AHLXI means..Load Register Pair with Immediate data.. 16bit dataLXI B ,2050HLoads BC pair with value 2050HB-> 20HC-> 50HIts similar to 2 MVI instructionieMVI H,20HMVI L,50Hwhich eventually implies..HL -> 2050Hthe advantage of LXI over MVI is that LXI is 3 byte and requires 10T states.Two MVI instruction is 4Byte and require 14Tstates...