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LHLD 2600h

is use to store data of 2600h in L register and data of 2601h in H register

While

SHLD 2600h

is use to store data of L in 2600h memory location and data of H in 2601h memory location data of H register

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Aman Shaikh

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4y ago

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Addition and subtraction of two 16 bit numbers using 8085 microprocessor?

The 8085 is an 8-bit computer, with only limited capability to do 16 bit arithmetic. In order to add two 16-bit numbers, NUM1 and NUM2, together, and store the result at NUM3, you can use the code... LHLD NUM1 XCHG LHLD NUM2 DAD D SHLD NUM3 If you want to subtract NUM1 from NUM2, you need to take the two's complement first, by inverting it and adding one... LHLD NUM1 MOV A,H CMA MOV H,A MOV A,L CMA MOV L,A INX H ... and then continue with adding NUM2... XCHG LHLD NUM2 DAD D SHLD NUM3


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Lxi b, 0000h lhld 8000h xchg lhld 8002h dcx d l006: lda 8002h add l mov l, a lda 8003h adc h mov h, a jnc l013 l013: inx b dcx d mov a, d ora e jnz l006 shld 8006h mov l, c mov h, b shld 8004h hlt


Does shld instruction affects the stackpointer in 8085?

SHLD...it basically stands for "store HL pair with data"... Explanation: HL pair is basically 2 registers H & L used together for specific purposes . This instruction stores the content of H & L registers into two consecutive memory locations (specified in the instruction). Better understand it with an example, SHLD 9000H means the processor will store the content of the "L" register in the location 9000H & that of the "H" register in the memory location 9001H. ROHIT DAS ECE CALCUTTA INSTITUTE OF TECHNOLOGY. (8287578929)


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