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The 8085 microprocessor lacks built-in support for floating-point arithmetic operations, which limits its capability for handling real numbers efficiently. Additionally, it does not have direct instructions for multiplication and division; these operations must be implemented using a series of simpler instructions. The 8085 also does not support hardware interrupts for all possible scenarios, as it can only handle a limited number of external interrupt requests. Lastly, it has no direct memory management capabilities, such as memory protection or paging.
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Which arithmetic instruction is available in 8086 but not in 8085?
The 8086 microprocessor includes the instruction for multiplication of unsigned integers, specifically the MUL and IMUL instructions, which are not available in the 8085 microprocessor. While the 8085 has basic arithmetic operations like addition and subtraction, the 8086's support for multiplication and division instructions allows for more complex arithmetic operations directly in hardware. Additionally, the 8086's capability to handle larger data sizes (16-bit) further distinguishes its arithmetic capabilities from the 8-bit 8085.
How is delay calculated in 8085?
The delay is calculated in 8085 by making the use of formulas. Because of the complexity of the mathematical operations a calculator may also be required.
What is the function of TMP register of ALU in 8085 microprocessor?
The TMP register in the 8085 is used to hold temporary results of operations. You cannot directly manipulate it, so you should just pretend it is not there.
Difference between 8080 and 8085?
The 8085 has a single +5V power supplyThe 8085 has a multiplexed low order address busThe 8085 has extra single pin interrupts, TRAP, RST7.5, RST6.5, and RST5.5The 8085 has serial I/O pins SID and SODThe 8085 has maskable interrupts and the RIM/SIM instructionThe 8085 includes the functionality of the 8224 clock genereator and 8228 system controllerThe 8085 added several 16 bit operations
Can 8085 CPU replace 8086 CPU?
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
Why masking is needed in 8085?
Masking in the 8085 microprocessor is necessary to selectively manipulate specific bits within a byte of data. It allows for operations such as isolating, setting, or clearing particular bits without affecting others, which is crucial for tasks like flag management and bitwise operations. By using a mask, programmers can efficiently control hardware interfaces and manage data in applications that require precise bit-level operations.
How do you initiate operations in 8085?
To initiate operations in the 8085 microprocessor, you first need to provide the necessary power supply and configure the system by connecting it to memory and input/output devices. The microprocessor starts executing instructions from a predetermined memory address, typically 0000H, after a reset. You then load the desired program into memory, and the 8085 reads and executes instructions sequentially, following the program flow. Finally, ensure that the control signals are properly set for communication with peripheral devices as needed.
What is meaning of 8085 microprocessor?
8085 is a 8 bit microprocessor designed by Intel.
Why the name 8085 Why the name 8085 for microprocessor?
8085 is a microprocessor designed by Intel
How many total instructions are there in 8085 MP?
there are 74 instruction sets in the 8085 up which consist of 246 bit pattern.
How many bits in 8085 microprocessor?
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
Why is the jump instruction jmp of 8085 microprocessor given the immediate addressing mode?
because the operand is available in the instruction itself
