There is no microprocessor with !t of address memory, only virtual memory. the firt one was the 80486.
Those are for people with terrible memory. If you can remember times, then you seriosuly shouldn't get one.
It depends upon the length of the data bit that is being stored in one memory address by the processor .
Logical address is the address generated by the CPU (from the perspective of a program that is running) whereas physical address (or the real address) is the address seen by the memory unit and it allows the data bus to access a particular memory cell in the main memory. All the logical addresses need to be mapped in to physical addresses before they can be used by the MMU. Physical and logical addresses are same when using compile time and load time address binding but they differ when using execution time address binding.
Direct address instructions specify the memory location of the operand directly within the instruction itself, requiring only one memory reference to fetch the operand. In contrast, indirect address instructions specify a memory location that contains the address of the operand, necessitating two memory references: one to retrieve the address and another to fetch the operand itself. Therefore, direct addressing is more efficient in terms of memory access.
A 16-bit address bus can address 2^16 distinct memory locations, which equals 65,536 individual addresses. Since each address typically corresponds to one byte of memory, this allows for the addressing of up to 64 kilobytes (KB) of memory (64KB = 65,536 bytes). Thus, a 16-bit address bus can effectively access all memory within this range.
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If the architecture allows each individual byte to be adressed then there are 4,000,000 possible addresses ranging from 0 to 3,999,999. So the largest address is 3,999,999 which is 3D08FF in hexadecimal representation
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A 16-bit address bus can address (2^{16}) memory locations, which equals 65,536 locations. Since each location typically represents one byte, the total memory is 65,536 bytes. To convert this into kilobytes (K), divide by 1,024, resulting in 64 K. Thus, a 16-bit address bus can address a total of 64 Kbytes of memory.
Computer memory is linear so a one dimensional array can be mapped on to the memory cells in rather straight forward manner.To find the actual address of an element one needs to subtract one from the position of the desired entry and then add the result to the address of the the first cell in the sequence.Having said that therefore it is necessary to know the starting address of the space allocated to the array and the size of the each element, which is same for all the elements of an array.The the location of the Ith element would be B+I*S where B is the base address(Starting address of the array) and S is the size of each element of the array.
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