Write program to add two 16 bit number using assembly language of Intel 8085?

Answer 1

Data segment

n1 db 20

n2 db 10

sum db ?

Data ends

code segment

assume cs:code,ds:data

start:mov ax,data

mov ds,ax

mov al,n1

mov bl,n2

add al,bl

mov sum,al

mov ah,4ch

int 21h

code ends

end start

Answer 2

This is a program to add two 16 bit numbers in which one number is stored at 8050 and 8051 and the 2nd number is stored at 8060 and 8061............

and the result is at 8070 and 8071

program:

LDA 8051H

LXI H,8061H

MOV B,M

MVI E,00H

ADD B

JNC L1

INR E

L1:STA 8071H

LDA 8050H

LXI H,8060H

MOV B,M

ADD E

ADD B

MVI E,00H

JNC L2

INR E

L2:STA 8070H

MOV A,E

STA 8072H

HLT

****************************************************************

LHLD 4000H : Get first I6-bit number

XCHG : Save first I6-bit number in DE

LHLD 4002H : Get second I6-bit number in HL

DAD D : Add DE and HL

SHLD 4004H : Store I6-bit result in memory locations 4004H and 4005H.

HLT : Terminate program execution

Sample problem:

(4000H) = 15H

(4001H) = 1CH

(4002H) = B7H

(4003H) = 5AH

Result = 1C15 + 5AB7H = 76CCH

(4004H) = CCH

(4005H) = 76H

************************************************ROCK FRANCIS***

Answer 3

Lhld 4000h

xchg

lhld 4002h

mov a,e

sub l

mov l,a

mov a,d

sub h

mov h,a

shld 4004h

hlt

********************************************************************

LHLD 4000H : Get first 16-bit number in HL

XCHG : Save first 16-bit number in DE

LHLD 4002H : Get second 16-bit number in HL

MOV A, E : Get lower byte of the first number

SUB L : Subtract lower byte of the second number

MOV L, A : Store the result in L register

MOV A, D : Get higher byte of the first number

SBB H : Subtract higher byte of second number with borrow

MOV H, A : Store l6-bit result in memory locations 4004H & 4005H.

SHLD 4004H : Store l6-bit result in memory locations 4004H & 4005H.

HLT : Terminate program execution.

Sample problem:

(4000H) = 19H

(400IH) = 6AH

(4004H) = I5H (4003H) = 5CH

Result = 6A19H - 5C15H = OE04H

(4004H) = 04H

(4005H) = OEH

Answer 4

Write a menu driven program to read two integers & find their sum, difference & product

Answer 5

once u check it from jntu spectrum