Head=Pressure X 2.3 For example: 70 psi. X 2.3 = 161 feet. Head=161 feet.
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10 m of water = 14 psi 1 m of water = 1.4 psi There is more to this... it should be as follows Pressure (P) = density of fluid (p)* gravity (g) * height of fluid (h) for example: p= ~1000 kg/m^3 (water at 20 deg C) g= ~9.81 m/s^2 (at sea level) h= 10 m of water Therefore: P=1000*9.81*10 P=~98,100 pascals (pa) = 98.1 kpa = 14.2 psi
If we have six (6) feet of water, that will convert to about 2.6 psi (pounds per square inch).
20 ft of head can be easily converted to psi by using the specific weight of water: 62.4 lb/ft3 and converting the units to inches. 20ft * 62.4lb/ft3 / 144in2/ft2 = 8.67 psi
The formula to convert water tank pressure (psi) to feet of head is: Feet = psi * 2.31. This formula is derived from the equation for hydrostatic pressure, which relates pressure to the height of a fluid column.
Multiply by 0.036 http://www.enercongroup.com/conversion_factors.htm One PSI is equal to 27.7 inches of water column
One foot of water at 62 degrees F = 0.433 PSI. To find the PSI for any feet head not listed, multiply the feet head by0.433.the answer would be 25.99 PSI in water at 62 Degrees Fahrenheit
To convert psi (pounds per square inch) to feet of water, you can use the conversion factor: 1 psi is equivalent to approximately 2.31 feet of water. This means that if you have a pressure of 1 psi, it would support a column of water approximately 2.31 feet high.
Multiply psi x 0.07 to get atmospheres.
To convert inches of water to psi (pounds per square inch), you can use the conversion factor: 1 inch of water is approximately equal to 0.0361 psi. Therefore, 11 inches of water would be calculated as 11 x 0.0361 psi, which equals approximately 0.3971 psi.
Head pressure is created by a column (depth) of water in a container. Pipe is considered a container. Diameter is not a factor. The higher the column of water, the more psi it creates. Multiply column height of water by .434 to get psi of water.
No thats why i am asking you if it is possible then give me answer or any possible answer