The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
To make 20 moles of sodium chloride, you would need 20 moles of sodium ions and 20 moles of chloride ions. This could be achieved by combining 40 moles of sodium atoms with 40 moles of chlorine atoms to form 20 moles of sodium chloride.
The moles of sodium hydroxide used can be calculated (moles = Molarity x Volume). Since it is a 1:1 reaction, the moles of hydrochloric acid neutralized will be the same. Using the moles and volume of hydrochloric acid, you can calculate its concentration (Molarity = moles / Volume).
0.1 M sodium hydroxide solution contains 0.1 moles of sodium hydroxide per liter of solution. This corresponds to 0.1 moles of NaOH per 40 g (1 mole) of NaOH, resulting in 4 g of NaOH in 1 liter of 0.1 M NaOH solution.
The molarity of a sodium hydroxide solution with a molecular weight of 40g containing 20g in 100ml of solution can be calculated as follows: Moles of NaOH = Mass of NaOH / Molecular weight of NaOH = 20g / 40g/mol = 0.5 moles Molarity = Moles of solute / Volume of solution in liters = 0.5 moles / 0.1 L = 5 M Therefore, the normality of this solution would be 5 N as normality is equal to molarity multiplied by the number of equivalents per mole of solute for sodium hydroxide, which is 1.
The chemical formula of sodium chloride is NaCl; formula is not dependent from the number of moles. Because the molecular mass of NaCl is 57,958 622 382, the mass of 20 moles is 1159,172 447 64.
The molar mass of sodium is approximately 23 g/mol. Therefore, 20 grams of sodium would be equivalent to about 0.87 moles of sodium.
20 ml
The viscosity of a 25% sodium hydroxide solution would be dependent on temperature. At room temperature (around 25°C), the viscosity of 25% sodium hydroxide solution is approximately 15-20 cP (centipoise).
109 -111 G IN 100ML WATER AT 20-25 DEG.C MUKESH BOTHRA
The balanced chemical equation for the reaction of lithium hydroxide with carbon dioxide is 2 LiOH + CO2 -> Li2CO3 + H2O. The mole ratio of LiOH to CO2 is 2:1, meaning that 40 moles of LiOH are required to react with 20 moles of CO2.
In 4 moles of magnesium hydroxide, Mg(OH)₂, there are a total of 20 atoms. Each formula unit of Mg(OH)₂ contains 1 magnesium atom, 2 oxygen atoms, and 2 hydrogen atoms, totaling 5 atoms per unit. Therefore, for 4 moles, you calculate 4 moles × 5 atoms/mole = 20 atoms.