Yes you can.
you should text
To properly format an APA in-text citation, you need to include the author's last name and the publication year in parentheses within the text of your paper. For example, (Smith, 2019).
L. L. Despard has written: 'Text-book of massage and remedial gymnastics' -- subject(s): Exercise therapy, Massage, Swedish gymnastics 'Text-book of massage'
To properly cite a movie in text, include the title of the movie in italics followed by the year of release in parentheses. For example, "The Shawshank Redemption (1994)."
To calculate the grams of LiCl needed to make a 2.0 L solution at a concentration of 0.65 M, use the formula: [ \text{grams of solute} = \text{molarity} \times \text{volume (L)} \times \text{molar mass} ] The molar mass of LiCl is approximately 42.39 g/mol. Thus: [ \text{grams of LiCl} = 0.65 , \text{mol/L} \times 2.0 , \text{L} \times 42.39 , \text{g/mol} \approx 55.85 , \text{g} ] Therefore, approximately 55.85 grams of LiCl are required.
Words to describe a woman starting with L are:lovelylevel headedlivelylazylovedleaderloyallittlelearnedlatelooneylucky
Old English Text MT assuming that you are talking about L from deathnote
To find the pressure of the butane sample, we can use the ideal gas law equation ( PV = nRT ). First, convert the temperature from Celsius to Kelvin: ( 2.0 , \text{C} + 273.15 = 275.15 , \text{K} ). Using the ideal gas constant ( R = 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} ), we can rearrange the equation to solve for ( P ): [ P = \frac{nRT}{V} = \frac{2.10 , \text{mol} \times 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \times 275.15 , \text{K}}{60.0 , \text{L}} \approx 0.96 , \text{atm}. ] Thus, the pressure of the butane sample is approximately 0.96 atm.
To properly in-text cite paragraphs in academic writing, include the author's last name and the year of publication in parentheses at the end of the paragraph. If the author is not mentioned in the text, include the author's name and year of publication in the citation.
To convert the capacity of a 26.0-gallon wine barrel to liters, use the conversion factor: ( 1 \text{ gal} = 3.7854 \text{ L} ). Thus, ( 26.0 \text{ gal} \times 3.7854 \text{ L/gal} = 98.55 \text{ L} ). The answer should have three significant figures, reflecting the precision of the given value (26.0 gal). Therefore, the final answer is 98.6 L.
To properly in-text cite a website with no author, use the title of the webpage in quotation marks followed by the publication date or the abbreviation "n.d." if no date is available (Author, n.d.).