| x | y | x' | y' | x⊕y | x'⊕y' |
----------------------------------
| 0 | 0 | 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 0 | 0 | 0 |
xor and xnor gates are derived from not gate
yes... xor is derived gate from primary gates
No, XOR gate is a not a universal gate. There are basically two universal gates NAND and NOR.
its not
To construct a 3-input XOR gate using 2-input XOR gates, you can connect the inputs in the following way: First, take two of the three inputs (let's call them A and B) and connect them to a 2-input XOR gate, producing an output (let's call it X). Then, connect the output X and the third input (C) to another 2-input XOR gate. The output of this second XOR gate will be the result of the 3-input XOR operation, effectively computing ( A \oplus B \oplus C ).
XOR (Exclusive OR) gate is exclusively for either. OR allows 10, 01, 11. XOR allows 10 or 01, but not 11.
XORing X with 1 gives X', i.e., NOT(X). If we are able to construct a NAND (AND) using XOR, we can also obtain AND (NAND) from it, which makes XOR a universal gate since inverted inputs to a NAND (AND) will give OR (NOR). However XOR is not a universal gate! Therefore we cannot obtain NAND (AND) using XOR. :-) By, Tirtha Sarathi Ghosh Class 10 IIT Kanpur Aspirant
XOR (Exclusive OR) gate is exclusively for either. OR allows 10, 01, 11. XOR allows 10 or 01, but not 11.
1 gate.
For 2-input EX-OR gate, if one input is A, the other input is B, and the output is Y. Then the Boolean expression for EX-OR (XOR) function (gate) is Y=A⊕B The output Y is true if either input A or if input B is true, but not both.Y= ( (A and NOT B) or (NOT A and B) ) ;
yes
Anot + Bnot +Cnot= y not meaning one single line on top of each letter.