citric acid
The chemical formula h3c6h5o7 does not follow conventional chemical naming conventions. Did you mean another chemical compound?
Three. Sometimes the formula is written H3C6H5O7 to indicate that.
The equation for Citric acid water would be HOCv(CH2Cooh)2 COOH + H2O. Citric acid is a weak organic acid that is a natural preservative.
The active ingredient in a Original Alka Seltzer tablet are Anhydrous citric acid (Anhydrous means that the substance has no water and is in a dry granulated form), and Sodium bicarbonate. (Sodium bicarbonate has many ways of being called, one is Sodium hydrogen carbonate, another way is Bicarbonate of soda and Baking soda) It also contains Aspirin.
The balanced equation for the reaction of sodium hydrogen carbonate (baking soda) and citric acid is: NaHCO3 + H3C6H5O7 ⟶ NaC6H5O7 + H2O + CO2 This reaction produces sodium citrate, water, and carbon dioxide gas.
Tri acidic bases are those which have three 'OH' group per unit as Al(OH)3 and Fe(OH)3, their one mole requires three mole of a base (NaOH) for complete neutralization.
The process of evaporation does not have a specific chemical equation since it is a physical process rather than a chemical reaction. Evaporation involves the conversion of a liquid into a gas due to an increase in temperature, leading to the escape of individual molecules from the surface of the liquid.
The two main chemicals that react in antacid tablets are typically calcium carbonate (CaCO3) and citric acid (H3C6H5O7). When these substances come into contact with stomach acid, a chemical reaction occurs that neutralizes the acid and helps alleviate symptoms of indigestion or heartburn.
When citric acid reacts with baking soda in water, it produces carbon dioxide gas, water, and sodium citrate. The chemical equation for this reaction is: H3C6H5O7 (citric acid) + 3 NaHCO3 (baking soda) -> 3 CO2 (carbon dioxide) + 3 H2O (water) + Na3C6H5O7 (sodium citrate).
To find the molality, we need to first calculate the molar mass of citric acid, which is 192.13 g/mol. Then, we calculate the moles of citric acid in 1 liter of solution (1.37 mol/L). Using the density, we can find the mass of 1 liter of solution (1100 g). Finally, we divide the moles by the mass of the solvent (in kg) to find the molality, which is 1.24 m.
The formula is C6H8O7citric-acidCitric acid's (C6H8O7) 'proper' name is 3-carboxyl-3-hydroxypentanedioc acid. This tells us that there is a carboxylic group at each end of chain of five carbon atoms. It also tells us that on the third carbon atom there is a hydroxyl group and another carboxylic group.I'm not sure for certain, but I'm pretty sure the structural formula for this is:COOHCH2COH(COOH)CH2COOH
3NaHCO3 + H3C6H5O7 = 3CO2 + 3H2O + Na3C6H5O7? 3NaHCO3 + H3C6H5O7 = 3CO2 + 3H2O + Na3C6H5O7How many moles of carbon dioxide can be produced if one tablet containing 0.0124 mol NaHCO3 is dissolved?is this your question?If so then , okay, first, since the 3CO2 is coming solely from the 3NaHCO3, you need to break those parts of the equation down to their constituent moles. We ignore the prefix (3) cos it is equal in both molecules.NaHCO3:1 molecule of Na (Sodium) = 231 molecule of H (Hydrogen) = 11 molecule of C (Carbon) = 123 molecules of O (Oxygen) = 16 X 3 = 48Total = 84CO2:1 molecule of C (carbon) = 122 molecules of O (oxygen) = 16 X 2 = 32Total = 44Since one tablet contains 0.0124 moles of NaHCO3, it follows therefore that the amount of CO2 produced will be:84 moles amounts to 0.0124Therefore 44 should amount to how much?(use simple proportion to calculate):(44 / 84) X 0.0124= 0.00649~ 0.0065 moles.So from the dissolution of a tablet containing 0.0124 moles NaHCO3, will produce 0.0065 moles of CO2.