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The answer depends on the accuracy desired.

a. The minimum bandwidth, a rough approximation, is B = bit rate /2, or 500 kHz. We need

a low-pass channel with frequencies between 0 and 500 kHz.

b. A better result can be achieved by using the first and the third harmonics with the required

bandwidth B = 3 × 500 kHz = 1.5 MHz.

c. A still better result can be achieved by using the first, third, and fifth harmonics with

B = 5 × 500 kHz = 2.5 MHz

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