When the vertical component of their velocity has dwindled to zero because of the
acceleration of gravity.
Things thrown upward fall back to the ground due to the force of gravity, which pulls objects towards the Earth's center. As the object rises, its speed decreases until the pull of gravity overcomes the upward force and causes it to fall back down.
Slower than the initial speed it was thrown upward with due to air resistance causing the ball to lose speed as it travels through the air. The force of air resistance acts against the direction of motion and slows down the ball.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
When two identical balls are thrown directly upward, they will follow the same path and reach the same height before falling back down due to gravity.
The velocity of a ball thrown upward at W ft/sec will gradually decrease due to gravity until it reaches its highest point (at which the velocity will be 0 ft/sec). After reaching the peak, the ball will then start to fall back down, increasing in velocity until it reaches the ground.
when abody is thrown upward,how many forces act on it?what is the role of the force with which the body has been thrown upward? After a body is thrown upwards, you have gravity pulling it down and friction slowing it.
When a ball is thrown upward, it experiences a brief period of acceleration while moving against the force of gravity. Once the ball reaches its peak height, it begins to fall back down due to gravity.
The gravity acting on a rising object and that on a falling object are the same when these objects are at the same height. What is different is that a rising object is decelerating by the force of gravity and the falling object is accelerating.
If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2. If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t − 16t^2.
Yes, when a ball reaches the top of its trajectory when thrown vertically upward, it is momentarily at rest before gravity pulls it back down. This is a state of dynamic equilibrium because the forces acting on the ball are balanced at that point.
The speed of the ball is greatest when it is thrown upward and decreases as it reaches the peak of its trajectory. The speed continues to decrease as the ball falls back down due to the force of gravity pulling it towards the ground.
Gravity acts as a downward force on objects that are thrown upwards, causing them to decelerate until they reach their peak height. At this point, their velocity becomes zero before gravity pulls them back down. As they descend, gravity accelerates them downwards, leading to an increase in their speed until they reach the ground. Ultimately, gravity ensures that all thrown objects return to the Earth's surface.