245m
200m. Here's the work:The speed of the train in meters per second is:(36km/hr)(1000m/km) / (3600s/hr) = 10 m/sIf it takes 80 seconds to cross, then the distance traveled in 80s at 10m/s is:(10m/s)(80s) = 800mNow, imagine this:The front end of the train travels 800 meters from the time it reaches the bridge until the back end is clear of the bridge. This means that the length of the train equals the distance traveled minus the length of the bridge.So:800m - 600m = 200mThe train is 200m long.
To totally cross the bridge the train must travel (850m + 150m) 1 km. 1 km in 100 seconds is 10 m/s roughly 20 mph, so the answer is yes, with ease.
30 seconds When the front of the train is at the start of the bridge, the back is still 50 metres away. When the back of the train crosses the bridge then the time stops. So 50 + 250 = 300 300 / 10 = 30
Assume Length of the train =x metre,speed be y metre/ sec Time taken to cross the pole x/y sec Time taken to cross the platform=length of train+length of platform/ speed of train x/y=15 x=15y x+100/y=25 15y+100=25y 10y=100 Y=10 metre/ sec x=15y = 100
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
its simple 72km/hr=72000m and 1hr=3600s........so train travelling per sec=72000/3600=20m........thus train travelling in 7s=140m which is answer :)
Along with motor vehicles the PATCO High Speed Line Commuter Train traverses this historic cable suspension bridge.
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Jacob Torino.
800 meters
A.120 metres B.180 metres C.324 metres D.150 metres
120 km/h = 120,000m/hr = 33.333 m/s Distance travelled in 50 seconds = 33.333 * 50 = 1666.666 metres Tunnel length = distance travelled - train length - 1666.666 - 135 = 1531.666metres