That is a very good question. But it is very hard to explain without the visualization of demonstration.
Ti(CN)4 is Titanium (IV) Cyanide
Ti(CN)4 is an ionic compound known as titanium(IV) cyanide. It is composed of titanium cations (Ti4+) and cyanide anions (CN-). The compound is often used in coordination chemistry and as a catalyst in organic reactions.
TiS for titanium sulfide (titanium(II) sulfide) and TiS2 for titanium disulfide (titanium(IV) sulfide)
Mn - Manganese(IV) has a 4+ charge CN - Cyanide has a 1- charge therefore... Mn(CN)4
The balanced equation for the reaction between Cu(NH3)4 and K4Fe(CN)6 is: 2Cu(NH3)4 + K4Fe(CN)6 -> Cu2Fe(CN)6 + 8NH3 + 4KCN
chemical formula for aluminum cyanide is Al(CN)3
Sn(CN)4
The valency of ferrocyanide is -4. This is because each cyanide ion (CN-) has a charge of -1, and there are four cyanide ions in the ferrocyanide complex [Fe(CN)6]4-.
The chemical formula of ferrocyanide is Fe(CN)6^(4-), where Fe represents iron and CN represents cyanide.
from midbrain = CN 3 (oculomotor) + CN 4(trochlear)from lateral of pons = CN 5 (trigeminal)at lower border of pons = CN 6 (abducens) + CN 7(facial) + CN 8 (vestibulo-cochlear)from medulla = CN 9 (glossopharyngeal) + CN 10 (vagus) +CN 11 (accessory) + CN 12(hypoglossal)Simply for addition, you must know that:CN that emerge close to midline = CN 3 + 6 + 12CN that emerge more laterally = CN 5 + 7 + 8 + 9 + 10 + 11The only CN that emerge from dorsal aspect = CN 4
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cn 3, 4 and 6