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What can be inferred about the current passing through the bulb?
The current passing through the bulb is directly related to the voltage applied across it and the resistance of the bulb. Using Ohm's Law (I = V/R), we can calculate the current flowing through the bulb by knowing the voltage and resistance values. Additionally, the brightness of the bulb can also be an indicator of the current passing through it, as higher current typically results in a brighter bulb.
Why is the voltage across a battery in a parallel circuit equal to the voltage across each bulb?
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.
Suppose in a circuit with 2 bulbs the resistance of bulb 1 is greater than that of bulb 2. how will the voltage across the two bulbs compare?
if the resistance of bulb A is 2x that of B then there will be twice as much voltage across it (ratio 2:1 ). both voltages shall equal the system voltage assuming they are in series and there are no other components in the circuit if the bulbs are in parallel the voltage across them will be equal and that of the system
Watt is the current allowed to flow through a bulb?
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
Connected in series or parallel will each bulb glow brighter?
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.
What is the reason for bulb becoming dim when connected in series?
the voltage across it is reduced, the voltage is shared with other bulbs
How is voltage determined on a light bulb?
Voltage on a light bulb is determined by the amount of electrical potential difference applied across its terminals. The higher the voltage, the brighter the bulb will shine. Light bulbs are typically rated to operate at a specific voltage, such as 120V for standard household bulbs.
How does the potential difference across the bulb in a flashlight compare to the terminal voltage of the batteries used to power the flashlight?
The potential difference across the bulb in a flashlight should be slightly lower than the terminal voltage of the batteries used to power the flashlight. This is because there is a small internal resistance in the batteries which causes a voltage drop across it.
How do you measure the voltageof a lightbulb?
You can measure the voltage of a light bulb by using a multimeter set to the voltage setting. Simply touch the positive and negative probes of the multimeter to the base of the light bulb where it connects to the socket to measure the voltage across the bulb.
How do you work out the current of a light bulb?
You can use Ohm's Law to calculate the current of a light bulb by dividing the voltage across the light bulb by its resistance, which is typically provided on the bulb itself or its packaging. The formula is: Current (I) = Voltage (V) / Resistance (R).
What is the difference between voltage output of a battery and the voltage across each DC bulb in a series circuit?
Exactly...you answered your own question. Each DC bulb will drop voltage according to its resistance and the amount of current it draws.
What s the correct calulation for the bulb power on watts which has has a current of 0.5 and the voltage is 220v?
Power is current times voltage, so a current of 0.5 amperes and a voltage of 220v across a bulb will yield a power of 110 watts.
