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A geometric sequence is defined recursively by an equals 12an-1 The first term of the sequence is 0.001 Which of the following is the explicit formula for the nth term of the sequence?
n=1 a(1) = 0.001 n=2 a(2) = 0.012 n=3 a(3) = 0.144 n=4 a(4) = 1.728 n=5 a(5) = 20.736 .... n=k a(k) = (12^(k-1))/1000 let n = k+1 a(k+1) = 12^(k)/1000 12(ak) = a(k+1) 12(12^k-1)/1000 = 12^k/1000 the 12 gets absorbed here. 12^(k-1+1)/1000 = 12^k/1000 Valid for k and k+1 therefore our equation A(n) = 12^(n-1)/1000, n(greater than or equal to) 1
Find the programming code for calculating the sum of the squares of the first 1000 numbers in HASKELL?
To get a list of the squares of the first 1000 numbers we can do:> [n^2 | n sum [n^2 | n
What is 1000 plus 999 plus 998 etc to 1?
There is an equation to find the sum of a list of numbers . It is called the Arithmetic Progression. The equation is S(n) = (n/2)[a + (n-1)d] 4 Where n = number of terms (1000) a = first term (1000) d = difference between terms (1) Hence S(1000) = (1000/2)[1000 + ( 1000 - 1)(1)] S(1000) = 500[ 1000 + 999] S(1000) = 500[1999] S(1000) = 999500 The answer!!!!!
How many kN in 23400 N?
1 N is equal to 1/1000 kN. 23400 is equal to 23400/1000=23.4 kN.
What is the smallest integer n such that the complete graph km has atleast 500 edges?
We know that the complete graph has n(n-1)/2 edges and we want to find out n such that n(n-1)/2 greater or equal to 500. Thus n(n-1) greater or equal to 1000. Taking n=33, we have, n(n-1)=33(33-1)=1056>1000. Therefore required smallest integer is n=33.
What is the sum of all the numbers from 1 to 1000?
well, ace of 1 (or the first number in the equation) =1, d=1 (or what it's added by each time), which shows that it's arithmetic), and n=1000 (the number you're trying to get)the equation is s of n=n/2 (ace of 1 + ace of n) s of n is the sum of the numbersso, s of n=500(1+1000)s of n=500500so 500,500 is the sum of the numbers from 1 to 1000.you can find more athttp://www.youtube.com/watch?v=VgVJrSJxkDk&feature=youtube_gdatahttp://www.youtube.com/watch?v=U_8GRLJplZg&feature=youtube_gdata
How many meters are n 1 kilometer?
1000 m
What is the nth term of 1 10 100 1000?
10^(n-1)
If you add up all the numbers from 1 to 1000 what do you get?
Sum of first n numbers = n/2(n +1) = 500 x 1001 = 500500
What is the sum of the integers 100 to 1000?
To find the sum of the integers from 100 to 1000, you can use the formula for the sum of an arithmetic series. The series has a first term (a) of 100, a last term (l) of 1000, and the number of terms (n) can be calculated as ( n = \frac{(l - a)}{d} + 1 ), where d is the common difference (1 in this case). This gives us ( n = \frac{(1000 - 100)}{1} + 1 = 901 ). The sum (S) can then be calculated using ( S = \frac{n}{2} (a + l) ), resulting in ( S = \frac{901}{2} (100 + 1000) = 450450 ). Thus, the sum of the integers from 100 to 1000 is 450450.
How many positive integers n from 1 to 1000 inclusive are there such that n is a multiple of 3 and the digit sum of n is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How do you find the total of 1to 10 1to 100 1to 1000?
To find the sum of 1 to 10, it helps to rearrange them, so instead of thinking of it like: 1 + 2 + . . . + 9 + 10, think like this: (1+10) + (2+9) + (3+8) + (4+7) + (5+6) = 11 + 11 + 11 + 11 + 11 = 5 x 11 = 55.So you have 5, which is 10/2 times 11 which is 10+1.Now to sum 1 to N, it is: (1 + N) + (2 + N-1) + (3 + N-2) + ... = (1+N) + (1+N) + ...., and you do that for N/2 times, so the answer is (1+N)*N/2.So for:N = 100 : 101*100/2 = 5050,N=1000 : 1001*1000/2 = 500500.
