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When was C. E. Byrd born?
C. E. Byrd was born on 1859-12-14.
If 12 E in a D equals 12 eggs in a dozen what is 12 D of C?
12 dozens in a carton?
What is C. E. M. Joad's birthday?
C. E. M. Joad was born on August 12, 1891.
What is the fifth number if there is a sum of four numbers that equal 40 when there is a fifth number added and the mean of the numbers become 12what is the fifth number?
The sum of four numbers equals 40: a+b+c+d=40 Those same four numbers, along with another number (e), give the set a mean of 12: (a+b+c+d+e)/5=12 Use these two facts to determine e as follows: (a+b+c+d+e)/5=12 a+b+c+d+e=60 (a+b+c+d)+e=60 40+e=60 e=20
What are the notes of 'the entertainer' in letters?
D D# E C E C E C C D D# E C D E BD C D D# E C E C E C AG F# A C E D C A D D D# E C E C E C C D D# E C D E B D C C D C E C D E C D C E C D E C D C E C D E E B D C #=sharp
What are the answers for AMC 12 2010?
The answers to the AMC 12A (American Mathematics Competition) from 2010 are: 1. C 2. A 3. E 4. D 5. C 6. E 7. C 8. C 9. A 10. A 11. C 12. D 13. C 14. B 15. D 16. B 17. E 18. D 19. A 20. C 21. A 22. A 23. A 24. B 25. C The answers to the AMC 12B 2010 are: 1. C 2. A 3. E 4. B 5. D 6. D 7. C 8. B 9. E 10. B 11. E 12. D 13. C 14. B 15. D 16. E 17. D 18. C 19. E 20. E 21. B 22. D 23. A 24. C 25. D
What are the notes for Jesus loves you?
e c c b c e e f f a f f e e e c c b c e e f f e a c b a e c e f a e c a c b e c e f a f e a c b a
What is the notes to forget you by Cee Lo Green for clarinet?
Well i can only tell you the first 12 notes which are: C E G A A G E D C D E and then its a low A
What is the drum and lyre chords of Nobody but you?
C c d e e e e e d c f c c d d d d d c b ec a c c c c c a a c c c c c a a e e e e e e e e e e e e ....
How old was E. C. Segar at death?
E. C. Segar died on October 13, 1938 at the age of 43.
What are the cuppy cake song notes on the piano?
c,c,f,f,f,f,c,f,f,f,f,f,c,f,f,e,d,c,c,c,e,e,e,e,e,e,e,e,e,e,e,d,c,c,d,e,f,c,c,f,f,c,c,c,f,f,f,c,c,c,f,f,e,d,c,c,c,e,e,e,e,e,e,e,d,c,c,d,e,f
What five numbers have a median of 12 a mode of 10 and mean of 12?
Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a ≤ b ≤ c ≤ d ≤ e, then:median = 12 → c = 12leaving only two numbers (a, b) ≤ 12.mode = 10 → two or more numbers equal 10 (which is less than 12) → a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 → d + e = 28 → d = 13, e = 15→ {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]
