20 Bottles in a Nebuchadnezzar (champagne)
N. B. Willey died on 1921-10-20.
20 numbers on a dartboard
20 Bottles (of Champagne) in a Nebuchadnezzar
The coefficient of ((x + y)^{20}) can be found using the binomial theorem, which states that ((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k). In this case, the coefficient of each term in the expansion is given by (\binom{20}{k}), where (k) is the exponent of (y) and (n-k) is the exponent of (x). The specific coefficient for any term ((x^a y^b)) can be determined by choosing (a) and (b) such that (a + b = 20). For the overall expansion, the sum of the coefficients for all terms is (2^{20}).
Station B-U-N-K - 1929 was released on: USA: 20 November 1929
i think 18 or 20 yrs of age........
#include<stdio.h> main() { char a[20],b[20]; printf("enter a string"); scanf("%s",&a); strcpy(b,a);//copies string a to b strrev(b);//reverses string b if(strcmp(a,b)==0)//compares if the original and reverse strings are same printf("\n%s is a palindrome",a); else printf("\n%s is not a palindrome",a); return 0; }
#include<stdio.h> #include<conio.h> void main() { printf("The first 20numbers of Fibonacci series are:"); int a=0, b=1, c, n=2; printf("%d \t, %d", &a, &b); while(n<20) { c=a+b; printf("\t %d", &c); a=b; b=c; n++; } getch(); }
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
Its spelt B-A-N-A-N-A-S its by Gwen Stephani
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
27 Explanation: formulae: n(A^B)=n(A)+n(B)-n(AvB) we have to findout n(B). n(B)=n(A^B)+n(AvB)-n(A) =10+50-30 =30 but here 3 members are not belongs to either of club members so, =30-3 =27. Now we got the result