S
A = letter 1 in alphabet
E = letter 5
F = letter 6
H = letter 8
In reverse:
Z = letter 26 (or letter 1 from back)
V = letter 22 (or letter 5 from back)
U = letter 21 (or letter 6 from back)
S = letter 19 (or letter 8 from back)
S
S
l
s
The next letter is L. Here is the sequence: a _ _ de _ _ hi _ _ lm.
The Answer would be the letter S A is the 1st letter, next is E which is the 5th, F is 6th, H is 8th. Then follow the sequence startin from the End of the Alphabet which is of course Z and do the same backwards. Z (1) V (5) U (6) S (8)
The next letter in the sequence is T. The sequence follows the alphabetical order, but jumps around by alternating the location of the letters in the alphabet.
The sequence alternates between skipping letters and decreasing the number of skipped letters. After ‘A’, we skip 3 letters to get to ‘E’, then skip 1 to get to ‘F’, skip 2 to get to ‘H’, skip 6 to reach ‘Z’, skip 4 to get to ‘V’, and then skip 1 to arrive at ‘U’. Following this pattern, the next letter should skip 2 letters after ‘U’, leading to the letter ‘R’.
I
a b c e d h so r h e u i d d h w i d x u f sif s
E U F H Z N and M
E , f , h , i, Z, U, , N