The playground is 26 feet long. x= playground length; y= playground width; p= playground perimeter= 94 x= y + 5 Perimeter= 2x + 2y 2x + 2y = 94 2(y+5) + 2y= 94 2y + 10 + 2y= 94 4y + 10= 94 4y= 84 y= 21; x= y +5= 26
yo brotha!
To find the perimeter of a room, measure the length and width of the room in feet. Use the formula for the perimeter of a rectangle, which is P = 2(length + width). For irregularly shaped rooms, measure each side and add all the lengths together to get the total perimeter.
The rectangle would be shaped like any other rectangle. To find the perimeter, add all four sides together. perimeter = 50ft + 50ft + 25ft + 25ft = 150ft
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
Two sides will enclose a lenticular (lens shaped) area. Its perimeter is 2.9 + 5.8 = 8.7 units of length.
Perimeter of a rectangle = 2*(H+W) = 2*(11+22) = 2*33 = 66 inches.
The perimeter of a rhombus-shaped highway sign with a 20-centimeter side is 80 centimeters.
LENGTH TIMES THE BREDTH
5000 feet ********** 5000 square feet is the AREA of the park (i.e. length x width). The perimeter is the total distance around the outside edge (i.e. 100 + 50 + 100 + 50), which is 300 feet. Pretty small park!
Only a rectangle.
Depends on the type of piano I guess. Most keyboards are rectangle shaped, there are rectangle/square shaped grand pianos but they are not common, most uprights are rectangle.
For Four sided shaped just Multiply the Length and Width, such as rectangle, square, rhombusetc.