Think Snooker: Black is 7, Pink is 6, Blue is 5. And there's ya answer. From Nightfire-Player. (no account here yet)
a^7 - b^7 = (a - b)(a^6 + a^5.b + a^4.b^2 + a^3.b^3 + a^2.b^4 +a.b^5 + b^6)
Provided that B is not an odd multiple of pi/2 thentan(B) = sin(B)/cos(B).Then, if B is measured in radians, thensin(B) = B - B^3/3! + B^5/5! - B^7/7! + ...andcos(B) = 1 - B^2/2! + B^4/4! - B^6/6! + ...
Provided that B is not an odd multiple of pi/2 thentan(B) = sin(B)/cos(B).Then, if B is measured in radians, thensin(B) = B - B^3/3! + B^5/5! - B^7/7! + ...andcos(B) = 1 - B^2/2! + B^4/4! - B^6/6! + ...
Commutative property. In this a+b = b+a eg 2+5=7 & 5+2=7 so (2+5)=7=(5+2)
Well, isn't that just a happy little math problem! If A is less than B and B plus C equals 10, then it must be true that A plus C is less than 10. Just remember, in the world of numbers, everything adds up beautifully in the end.
1.B 2.a 3.b 4.b 5.a 6.a 7.a 8.b 9.c 10.a
(a + b) + c = a + (b + c) the parenthesis means you are supposed to add a and b first on the left, but the property tells you it is ok to regroup and add b and c first... you will get the same answer ( 3 + 6) + 7 gives the same answer as 3 + (6 + 7)
The statement "B is 7, P is 6, B is 5" appears to present conflicting information about the values assigned to B. If B is 7 in the first instance but is also stated to be 5 later, this inconsistency suggests that the context or conditions under which B is defined may have changed. Meanwhile, P remains consistently defined as 6. Clarifying the context or the rules governing these values would be necessary to resolve the contradiction.
B/5 = 6 means that 6 x 5 = B 6 x 5 = 30 Therefore, B = 30
int a, b; b = 5; /* post-increment operator */ a = b++; /* a is now 5, and b is now 6. */ /* pre-increment operator */ a = ++b; /* a and b are now both 7 */
The algebraic expression for "6 more than the difference of b and 5" can be written as (b - 5) + 6. This expression first calculates the difference between b and 5 by subtracting 5 from b, then adds 6 to the result. This can also be simplified as b + 1, as subtracting 5 and adding 6 cancels out to adding 1.
What is the answers to -7 ( a + b - 5 ) + 8 ( -3a +2b ) + b ( 7 + 3 )