T in C = ( T in F - 32.0 ) ( 5/9 )T in C = ( 15 - 32.0 ) ( 5/9 ) = -9.4 C
The temperature T in degrees Celsius (°C) is equal to the temperature T in degrees Fahrenheit (°F) minus 32, times 5/9: T(°C) = (T(°F) - 32) × 5/9 Convert 68 degrees Fahrenheit to degrees Celsius: T(°C) = (68°F - 32) × 5/9 = 20 °C
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The four temperature scales are Celsius ( C ) , Fahrenheit ( F ), Kelvin ( K ), and Rankine ( R ).T in C = ( 5/9 ) ( T in F - 32.0 )T in F = ( 9/5 ) ( T in C ) + 32.0T in K = T in C + 273.2T in R = T in F + 459.7
You have the following relationships:T in C = ( 5/9 ) ( T in F - 32.0 )T in C = ( 5/9 ) ( 350.0 - 32.0 ) = 176.7 C
You have the following relationships:T in C = ( 5/9 ) ( T in F - 32.0 )T in C = ( 5/9 ) ( 350.0 - 32.0 ) = 176.7 C
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W-I-T-C-H- - 2004 I Is for Illusion 2-9 was released on: USA: 9 August 2006
The relationship between Celsius and Fahrenheit is:c = (5 / 9) * (f - 32)So if they are equal, we can simply note that c and f are equal in that equation, and then solve it. Let' call them both "t":t = (5 / 9) * (t - 32)∴ t = (5t - 160) / 9∴ t = 5t/9 - 160/9∴ t - 5t/9 = -160/9∴ 4t/9 = -160/9∴ 4t = -160∴ t = -40So -40°F = -40°C
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C-P-T- - 2011 was released on: USA: 9 February 2011
As we know that the relation between T(F) and T(C) is given by: T(F)=9/5*T(C)+32 Now we want to know the point at which T(F) and T(C) both agrees i.e T(F)=T(C) So the above expression becomes, T(F)=9/5*T(F)+32 By solving above we get -40oC