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It is certainly possible, though the second player is at a disadvantage.

The standard variant of Mancala is solved as having a winning stragety. What this means is, if the first player is perfect, they will always win. Such optimal play is unlikely to be seen unless a super-computer is playing without time-limit.

So, how easy is it for the starting player to mess up? Some of the starting moves available to the first player provide a configuration where the second player has a winning strategy. This suggests that the second player needs to deviate from optimal play only slightly less often than the first player in order to win.

The advantage of going first at least appears to be rather small.

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