How can 1 and 17 and 18 and 19 and 20 equal 50?

Answer 1

its impossible retards go back to grade school

xxxxxxxxxxxxxxxxxxxxxxx It is impossible even if you use a different arithmetic base example: base 16 1 (b16) = 1

17 (b16) = 23 18 (b16) = 24 19 (b16) = 25 20 (b16) = 32 Total = 105 50 (b16) = 80 The total will always be 25 more than "50" in whatever base is used.

Call the base "x"

The total of the 5 sums is 1+(x+7)+(x+8)+(x+9)+(2x) = 5x+25

50 in base x = 5x