Twelve: the fifth card can be anything but a queen.
eleventeen
There are 1716 of them.
There are C(4,4) combinations of 4 queens and C(48,1) combinations for the remaining card. So: 1x48 = 48 different 5 card hands containing 4 queens. Remember, the order of the 4 queens is irrelevant so there is only 1 combination of 4 queens. This only leaves 48 more card to choose from for the remaining card.
There are 2,598,960 5-card hands. This is combinatorials, which is used in probability but is not probability itself.
There are 2597673 such hands.There are 2597673 such hands.
If the cards are all different then there are 13C7 = 1716 different hands.
To determine the number of possible 6-card hands from a 26-card deck, you can use the combination formula ( \binom{n}{r} ), where ( n ) is the total number of cards and ( r ) is the number of cards drawn. Here, ( n = 26 ) and ( r = 6 ). Thus, the number of 6-card hands is calculated as ( \binom{26}{6} = \frac{26!}{6!(26-6)!} = 26,234 ). Therefore, there are 26,234 possible 6-card hands.
There are 1584 hands possible with 2 Kings, 2 Jacks and 1 other card which is not a King or a Jack.
4 kings, 4 queens, and 4 jacks.
This is a permutation, which is from 52 select 3, or52P3, or 132600. The other way to think of this is you have 52 choices for the first card, 51 choices for the second card, and 50 choices for the third card. Therefore you have 52*51*50 possible hands or 132600.
4 Queens in a pack of 52 cards.
None; a standard 52-card deck has two red queens and two black queens.