To find the number of different 2-letter arrangements from the set (S, H, A, R, K), we can use the formula for permutations since the order matters. There are 5 letters in total, and for the first letter, we have 5 options, and for the second letter, we have 4 remaining options. Thus, the total number of 2-letter arrangements is (5 \times 4 = 20).
32
32
Only 20.
Only 20.
There are 3780 different arrangements.
There are 172 different arrangements.
There are 6! = 720 different arrangements.
64 different arrangements are possible.
There are 7!/(2!*2!) = 1260 arrangements.
6! = 6x5x4x3x2x1 = 720 arrangements
There are 5!/2! = 60 arrangements.
40,320