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None in either the Scrabble dictionary, or Webster's Second International dictionary. Both dictionaries contain over 250,000 words each.

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How many distinguishable permutations are there of the letters of the word rectangle?

The word "rectangle" consists of 9 letters, with the letter 'e' appearing twice and all other letters being unique. To find the number of distinguishable permutations, we use the formula for permutations of a multiset: (\frac{n!}{n_1! \cdot n_2! \cdots n_k!}), where (n) is the total number of letters and (n_i) are the frequencies of the distinct letters. Thus, the number of distinguishable permutations is (\frac{9!}{2!} = \frac{362880}{2} = 181440).


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How many distinguishable and indistinguishable permutations are there in the word algrebra?

The word "algrebra" has 8 letters, with the letter 'a' appearing twice and 'r' appearing twice. To find the number of distinguishable permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of distinguishable permutations is ( \frac{8!}{2! \times 2!} = 10080 ). Since all letters are counted in this formula, there are no indistinguishable permutations in this context.


How many 3-letter codes can be formed from the letters in the wped picture if letters cannot be repeated?

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There is no seven letter word spelled with the letters 'eeylhbi'.Words that can be spelled with those letters are:bebeebeliebilebybyeeeleyeheheelheyhihieIleeleiliblielyeye


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Find the number of distinguishable permutations of letters in the word appliance?

The distinguishable permutations are the total permutations divided by the product of the factorial of the count of each letter. So: 9!/(2!*2!*1*1*1*1*1) = 362880/4 = 90,720


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