In the word "OBJECTIVE," there are 9 letters in total. To find the number of pairs of letters, we use the combination formula for choosing 2 letters from 9, which is calculated as ( \binom{9}{2} = \frac{9 \times 8}{2 \times 1} = 36 ). Therefore, there are 36 pairs of letters in the word "OBJECTIVE."
In the word "misplace," we need to find pairs of letters that have the same number of letters between them as they do in the English alphabet. The pairs are: (m, p), (i, s), and (l, e). Each of these pairs has 2 letters between them in the alphabet, matching the spacing in the word. Thus, there are three such pairs.
In the word "Stainless," we can analyze the pairs of letters to find those that have the same number of letters between them in the word as in the English alphabet. The pairs that meet this criterion are (S, T) and (S, N). Thus, there are 2 such pairs of letters in the word "Stainless."
The pairs DE and OP are consecutive, as in the alphabet. The pair PT are separated by 3 letters, as they are by the letters QRS. The pair OT are separated by 4 letters, as they are by the letters PQRS.
Two pairs of letters are there in the word ANSWER. 1) AnswE(AbcdE) - AE 2) NsweR(NopqR) - NR
2
De, on = 2
Three pairs of letters are there. E and G, G and I & L and N are those three pairs.
7
2 xa: 2xi; 2xt; = 3 pairs in total
Castraphone is not a word!However...the answer is 4 pairs of letters...# ST (ST) # RaP (PqR) # HonE (EfgH) # ON (NO)
sixty-twelve
Two, that I found.