11x8 - 9x9 = 7
In order to be able to give the answers for English rules 7 sheet 15 it is necessary to know the list of questions. Some worksheets may have their answers printed on various websites but not all of them do.
We don't have access to math sheet lesson 7. Perhaps you could tell us some of the problems and we could show you how to solve them.
Ask your teachers for an answers sheet
No because 9❌9=81 and 11❌7=77
I am sorry but you need to figure things out instead of looking them up on the internet
I'm sorry, I don't have that one in front of me.
Well, honey, I don't have a crystal ball to magically know the answers to your Maths mate 7 term 3 sheet 3. You gotta put in the work and figure it out yourself. Trust me, the satisfaction of solving it on your own is worth way more than any answer I could give you.
There are N = 6670903752021072936960 6.671×1021 valid Sudoku grids. Taking out the factors of 9! and 722 coming from relabelling and the lexicographical reduction of the top row of blocks B2 and B3, and of the left column of blocks B4 and B7, this leaves 3546146300288 = 27×27704267971 arrangements, the last factor being prime. 9^9 x 8^9 x 7^9 x 6^9 x 5^9 x 4^9 x 3^9 x 2^9 x 1^9 = 362880^9
Seven of them because 63/9 = 7
Enter a number in each circle so that the number on each line equals the sum of the numbers at each end
I am assuming you are referring to a normal 3x3 sudoku grid, where you can only use the numbers 1-9 once in the grid, and by prime number you mean the 3digit number across and down the grid must be prime? For a number to be prime, it must end in 1, 3, 7 or 9. There are 5 places on the Sudoku grid for a number to finish and as you can only use a number once in sudoku you have one place left where the number can not be prime. This means the most you can have is 5 prime numbers.