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How many ways can you arrange the letters PARTY if the first letter must be an A?
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
What word can you spell with the letters TIFBG And you must use all letters?
It is not a word. It is an acronym: IFTGB is the Institute of Forest Genetics and Tree Breeding in Tamil, Nadu, India.
6 letter word x is second letter and d is fourth letter. the first and fifth letters must be the same letter?
Exuded or exudes.
How many 7-letter words can be formed from the letters of the word Marble if each word must start with M?
There are no 7 letter words that can be formed from the letters of the word MARBLE, because MARBLE only has six letters.
What seven letter word has the letters c p u e s l o and must begin with the letter c?
There are two seven letter words beginning with 'C' that can be formed from these letters. They are:CloseupCouples
How do you obtain letters testamentary in Washington?
To obtain a letter of Testamentary, you must petition the government. To obtain the letter, you must have a proper ID of the deceased person and the appropriate title to be able to receive that letter.
Which letter parts are keyed at the tab you must set when keying a modified block letters?
The keyed letter parts into set keying to modidied block letters are dateline and the closing lines.
What can you spell with the letters j p c h d?
You must add a vowel to spell a word with those letters.a + jpchd will spell chap or hadj;e + jpchd will spell he;i + jpchd will spell chip or dip;o + jpchd will spell do or chop;u + jpchd will spell cup or cud.
What are two basic rules for writing symbols of elements?
The first letter must be capitalized and all others must remain lower case.
What must identifiers start with?
the name of an identifier consists of letters and digits but name always starts with a letter.
How many three letter palindromes are there?
A three-letter palindrome has the form ABA, where A and B are letters. The first and last letters (A) must be the same, while the middle letter (B) can be any letter. Assuming we use the 26 letters of the English alphabet, there are 26 options for A and 26 options for B, resulting in 26 × 26 = 676 three-letter palindromes.
How many different arrangements of 5 letters can be formed if the first letter must be W or K and 8203 (repeats of letters are and 8203 allowed)?
If the first letter must be either W or K, there are 2 choices for the first letter. For the remaining 4 letters, since repeats are allowed, each can be any of the 26 letters in the alphabet. Therefore, the total number of arrangements is (2 \times 26^4), which equals (2 \times 456976 = 913952).
