N.G.A.F means "Not Givning A (Profane)
No, if f(n) o(g(n)), it does not necessarily imply that g(n) o(f(n)).
If f(n) o(g(n)), it means that the growth rate of f(n) is smaller than the growth rate of g(n).
this is not correct F F F F F F F G A G F F F G F A N D A A J B E D J I N G
∫ f(x)/[f(x) + g(x)]n dx = ∫ 1/[f(x) + g(x)]n - 1 dx - ∫ g(x)/[f(x) + g(x)]n dx
G. F. N. has written: 'Tit for tat for the Lord knows what'
S-U-F-F-E-R-I-N-G
F. G. M. N. Poelhekke has written: 'Guinee-Bissau'
To prove that the function f(n) is big theta of g(n), you need to show that there exist positive constants c1, c2, and n0 such that for all n greater than or equal to n0, c1g(n) f(n) c2g(n). This means that f(n) grows at the same rate as g(n) within a constant factor for sufficiently large n.
You meant:MARICÓN --- a very offensive word for a man or a homosexual man, like "f-a-g"
While no set of rules can handle differentiating every expression, the following should help. For all of the following, assume c and n are constants, f(x) and g(x) are functions of x, and f'(x) and g'(x) mean the derivative of f and g respectively. Constant derivative rule:d/dx(c)=0 Constant multiple rule:d/dx(c*f(x))=c*f'(x) Sum and Difference Rule:d/dx(f(x)±g(x))=f'(x)±g'(x) Power rule:d/dx(xn)=n*xn-1 Product rule:d/dx(f(x)*g(x))=f'(x)*g(x) + g'(x)*f(x) Quotient rule:d/dx(f(x)/g(x))=(f'(x)*g(x)-g'(x)*f(x))/f(x)² Chain rule:d/dx(f(g(x))= f'(g(x))*g'(x)
It's spelled F-R-I-G-H-T-E-N-I-N-G.
W t f n i g g a