7/14 = N/6 7x6=14N 42=14N N=3
n = 14 half of 14 is 7 and 7 minus 6 is 1
20-2n when n = 7. just take 20-2(7) replace n with 7. then use the PEMDAS rule. 2(7) = 14, then 20-14 = 6
7 + n = 14 n = 7
To find the number of hockey teams of 6 players that can be formed from 14 players, we use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 14 ) and ( r = 6 ). Thus, the calculation is ( C(14, 6) = \frac{14!}{6!(14-6)!} = \frac{14!}{6! \cdot 8!} ), which simplifies to ( 3003 ). Therefore, 3003 different teams of 6 players can be formed from 14 players.
n/6 = 14 n = 6*14 n = 84
9/6 = 21/n3/2 = 21/n Since 3 x 7 = 21, then n must be 14 (2 x 7) and we have:3/2 = 21/14 or 9/6 = 21/14.
Set it up this way: 8n + 7 = 2n Take 7 away from each side. 8n = 2n - 7 Take 2n away from each side 6n = -7 Divide each side by 6 n = -7/6 To check the answer, replace the n's with -7/6. 8 X -7/6 + 7 = 2 X -7/6 -56/6 + 42/6 = -14/6 -14/6 = -14/6
18
C-13 has an atomic number of 6 and an atomic mass of 13, therefore it has 13-6 neutrons = 7. C-14 therefore has 8 neutrons. N-14 has an atomic mass of 14 and an atomic number of 7, so its number of neutrons is 7. 8>7, so Carbon 14 has the largest number of neutrons.
14 ! If n=12, then 12-4 is 8, plus 6 is 14
6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.