90 Minutes in a football match
90 minutes played in a football match
Let M equal the gallons of the 90% mixing solution. Let F equal the gallons of the final solution. So:90 + M = F.Also, the number of gallons of pure antifreeze in the final will equal the sum of the gallons of antifreeze in the two mixing parts:Original solution: ( 90 gal )*(0.15) = 13.5 gal [0.15 represents 15%]Mixing solution: M*0.90Final solution: F*0.80So 13.5 + M*0.90 = F*0.80Now you have 2 linear equations and 2 unknowns, you can solve for M & F, using your favorite method: M = 585 and F = 675. Add 585 gallons of the 90% to get 675 gallons of 80% solution.
105
f = m a a = f / m = 30/90 = 1/3 meter per second2= roughly 1/30th of gravity
m2+m-90 = (m-9)(m+10) when factored
90 m = 90,000 millimetres.
To find the acceleration of the shot put, you can use Newton's second law of motion, which states that ( F = ma ), where ( F ) is the net force, ( m ) is the mass, and ( a ) is the acceleration. Rearranging this gives ( a = \frac{F}{m} ). Plugging in the values, ( a = \frac{90 , \text{N}}{5.5 , \text{kg}} \approx 16.36 , \text{m/s}^2 ). Therefore, the acceleration of the shot put is approximately 16.36 m/s².
Force = F, mass = m, acceleration = a From Newton's second law: a = F/m F = m X a m = F/a
F = MA M = F / A A = F / M
M < 90
If f = -19 when m = 14 then, when m = 2, f = -19/7.
it is so easy m<90