The answer to the sum of b and 4 is expressed as ( b + 4 ). This means you take the value of b and add 4 to it. The specific numerical result depends on the value of b.
It is: 4(12+b) which is the same as 48+4b
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
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h = 4 and 8 +4=12
1.Start 2. Input a,b,c 3. Sum = a+b+c 4. Average = sum/3 5. Output - Sum,Average 6. Stop
4(2a+b) + 2(6a+2b) Working this out it is: 8a + 4b + 12a + 4b = 20a + 8b or 4(5a+2b).
This problems requires you to solve using simultaneous equations. EQUATIONS: a + b = 4 a = 4 - b CALCULATE b: a * b = 15/4 = 3.75 b = 3.75/a b = 3.75/4-b b * (b4-4) = 3.75 b2 * 4b = 3.75 (b * 4)2 = 3.75 b * 4 = SQRT(3.75) b = SQRT(3.75)/4 b = 0.484122918275927 CALCULATE a: a = 4 - .484122918275927 a = 3.51587708172407 PROOF: a + b = 4 3.51587708172407 + 0.484122918275927 = 4
"the same as the others added together" For example: a=b+c+d a is equal to the sum of b plus c plus d. 9=2+3+4
int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
To find the sum of two vectors, you add their corresponding components together. For example, if you have two vectors A = (3, 5) and B = (2, -1), the sum would be A + B = (3 + 2, 5 + (-1)) = (5, 4).
To solve the sum and difference of two terms, you can use the identities for the sum and difference of squares. For two terms (a) and (b), the sum is expressed as (a + b) and the difference as (a - b). To find their product, you use the formula: ((a + b)(a - b) = a^2 - b^2). This allows you to calculate the difference of squares directly from the sum and difference of the terms.