0
What else can I help you with?
Did the Russians win the Russian Revolution?
Given that during the Revolutions Russians were fighting Russians, you could say that Russians won. You could also say that Russians lost.
Did Russians descend from Ancient Rome?
No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.No, the Russians did not descend from the ancient Romans. Anthropologists say that modern Russians are of Slavic descent.
What is a group of Russians called?
Russians.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
Have the Russians returned to Russia?
The Russians are in Russia.
What is Russophobia?
Fear of Russians Fear of Russians
What is a antonym of pale?
Tan Tan
What percentage of ethnic Russians are Slavic?
Answer: All ethnic Russians are Slavic.
What was the Russians MIR?
the Russians MIR is a controll in space
Why are Russians better than anybody?
Because they are Russians
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
How many members are in Russians today?
1,400,000 people are russians.
