How far is Sarasota FL from the equator?

Answer 1

Sarasota, Florida, is located at approximately 27.3 degrees north latitude. The equator is at 0 degrees latitude, so Sarasota is about 27.3 degrees north of the equator. To convert this latitude into distance, you can estimate that each degree of latitude is roughly 69 miles (111 kilometers). Therefore, Sarasota is approximately 1,885 miles (3,034 kilometers) north of the equator.