200
{| class="tdefault" | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |- | width="369" | | width="369" | |} ---- === === === === === === === ===
class width is a width width is a width nothing as class width is a width dont be confuse
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
length*width = 2*width*width i.e square the width and multiply by 2
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET
no it does not have a width
What is the width of Tennessee
{| ! width="150" | 1989: | 68,118 ! width="150" | 1990: | 60,582 ! width="150" | 1991: | 34,534 ! width="150" | 1992: | 27,033 ! width="150" | 1993: | 21,471 ! width="150" | 1994: | 1,391 ! width="150" | 1995: | 25,114 ! width="150" | 1996: | 7,334 ! width="150" | 1997: | 3,655 ! width="150" | 1998: | 2,178 ! width="150" | Total: | 251,410 |}
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It is 22 in by 27 in. ------------------------------------------- How it is solved: The rectangle is 5 in longer than its width, so the dimensions can be given in terms of its width: Its dimensions are width by (width+5) In removing 1 inch squares from the corners, he flaps are going to be (width-2) and (width+5-2) = (width-3) long. Thus the box formed will have volume: volume = (width - 2) in × (width + 3) in × 1 in → volume = width² + width - 6 in³ But we are told this is 500 in³; thus: width² + width - 6 in³ = 500 in³ → width ² + width - 506 = 0 → (width + 23)(width - 22) = 0 → width = -23 or 22 As a length cannot be negative, the width must be 22 in which means the original rectangle is 22 in by 22+5 in = 27 in