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You can calculate that on any scientific calculator. Make sure you put it into the correct angle mode (degrees, or radians, depending on what you need), and press something like "inverse", followed by "sin".In Excel, you can type:

=asin(0.58333)

That will give you the angle in radians.

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Solution for tan x is equal to cos x?

Tan(x) = Sin(x) / Cos(x) Hence Sin(x) / Cos(x) = Cos(x) Sin(x) = Cos^(2)[x] Sin(x) = 1 - Sin^(2)[x] Sin^(2)[x] + Sin(x) - 1 = 0 It is now in Quadratic form to solve for Sin(x) Sin(x) = { -1 +/-sqrt[1^(2) - 4(1)(-1)]} / 2(1) Sin(x) = { -1 +/-sqrt[5[} / 2 Sin(x) = {-1 +/-2.236067978... ] / 2 Sin(x) = -3.236067978...] / 2 Sin(x) = -1.61803.... ( This is unresolved as Sine values can only range from '1' to '-1') & Sin(x) = 1.236067978... / 2 Sin(x) = 0.618033989... x = Sin^(-1) [ 0.618033989...] x = 38.17270765.... degrees.


Is sin 2x equals 2 sin x cos x an identity?

YES!!!! Sin(2x) = Sin(x+x') Sin(x+x') = SinxCosx' + CosxSinx' I have put a 'dash' on an 'x' only to show its position in the identity. Both x & x' carry the same value. Hence SinxCosx' + CosxSinx' = Sinx Cos x + Sinx'Cosx => 2SinxCosx


Which trig expression is equal to sin (72 and Acirc and deg - a)?

The expression ( \sin(72^\circ - a) ) can be rewritten using the sine difference identity: [ \sin(72^\circ - a) = \sin(72^\circ) \cos(a) - \cos(72^\circ) \sin(a). ] Thus, ( \sin(72^\circ - a) ) is equal to ( \sin(72^\circ) \cos(a) - \cos(72^\circ) \sin(a) ).


What are five trigonometric identities?

All others can be derived from these and a little calculus: sin2x+cos2x=1 sec2x-tan2x=1 sin(a+b)=sin(a)cos(b)+sin(b)sin(a) cos(a+b)=cos(a)cos(b)-sin(a)sin(b) eix=cos(x)+i*sin(x)


Sin3alfa equals to?

The expression (\sin(3\alpha)) can be expanded using the triple angle formula for sine, which is (\sin(3\alpha) = 3\sin(\alpha) - 4\sin^3(\alpha)). This formula allows you to express (\sin(3\alpha)) in terms of (\sin(\alpha)).

Related Questions

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