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A 3.5 INR (International Normalized Ratio) reading is considered higher than the typical therapeutic range for most patients, which is usually between 2.0 and 3.0 for those on anticoagulants like warfarin. A reading of 3.5 may increase the risk of bleeding complications, and it's important to consult a healthcare provider to assess the situation and determine if any adjustments to medication or monitoring are necessary.
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What is the value of tan of 35 degrees?
Tan(35) = 0.700207.... However, Tan = Sin/ Cos Hence Tan(35) = Sin(35) / Cos(35) = 0.57357... / 0.81915... & 0.57357... / 0.81915.... = 0.7002.... As before!!!!!
If a tree casts a shadow of fifteen meters long how tall is the tree?
Not enough information has been given to solve this problem such as: What is the angle of elevation?
From a point on the ground 24 feet from the base of a tree the angle of elevation of the top of the tree is 35 degrees what is the height of the tree?
Using the expression for tangent: tan(angle)=opposite/adjacent, and x to denote the height of the tree, we have tan(35)=x/24 So x=24*tan(35) = 24*0.4738 = 11.37 So the tree is 11.37 feet tall
What is the value of x and y of the vectors below a 45 m-W b 20 m -60 deg SW c 76 m -35 deg NW d 43 m -58 deg SE e 35 m -40 deg NE Thanks xx?
To find the values of x and y for the given vectors, we can use trigonometric functions to resolve each vector into its components. a) For 45 m at 0 degrees (due East): ( x = 45 , \text{m}, , y = 0 , \text{m} ) b) For 20 m at 60 degrees SW (which is 240 degrees): ( x = 20 \cos(240^\circ) = -10 , \text{m}, , y = 20 \sin(240^\circ) \approx -17.32 , \text{m} ) c) For 76 m at 35 degrees NW (which is 325 degrees): ( x = 76 \cos(325^\circ) \approx 62.25 , \text{m}, , y = 76 \sin(325^\circ) \approx -43.67 , \text{m} ) d) For 43 m at 58 degrees SE (which is 132 degrees): ( x = 43 \cos(132^\circ) \approx -25.81 , \text{m}, , y = 43 \sin(132^\circ) \approx 34.48 , \text{m} ) e) For 35 m at 40 degrees NE (which is 40 degrees): ( x = 35 \cos(40^\circ) \approx 26.83 , \text{m}, , y = 35 \sin(40^\circ) \approx 22.49 , \text{m} ) Please let me know if you would like the calculations for a specific vector or if further details are needed!
How long did Cyclone Tracy last?
Cyclone Tracy hit Darwin just after midnight on Christmas Day in 1974 and lasted until about 7:00 am.The eye itself took about 35 minutes to pass.
How many Indian rupees in 35 million dollar?
138 crores in INR
What level of ast is too high?
is 232 ast level dangerous
Is 35 too young to have a heart attack?
No, 35 is not too young to have a heart attack.
Is a 35 high on the Rockwell C Scale?
If 35 HRC is high on the Rockwell scale or not is quite relative to what you would define as high. A typical axe would rate at around 45-55 HRC, while high quality steel knives would rate at about 55-66 HRC.
Cody is reading a book he is on a page that is after 30 but before 35 the sum of the two digits equals 6 What page is Cody reading?
Cody is reading page 33.
How old would you be on Venus if you were 35 on earth?
You would be 35 on Venus too.
Is 35 a muiltiple of 6 and why?
No because when you muiltiple by 6*6 you will get 36 but thats too high so you do 5*6 and that equals 30 thats too low so I was thinking maybe 6 is not a muiltiple of 36.
What goes in too 243?
33333243 = 35
How old is too old to be an attorney?
35
How many kilometers is Reading from London?
35 miles (56 kilometres) taking M4.
Is 50 psi too high for a tire pressure?
Yes, 50 psi is too high for a tire pressure. The recommended tire pressure for most vehicles is typically between 30-35 psi. Overinflating the tires can lead to reduced traction, uneven wear, and potential blowouts.
How do you calculate for arriving square root of 625?
Since the number ends in 5, the square root (if an integer) will end in 5. 15 squared is too low, 35 squared is too high. 25 x 25 = 625
