answersLogoWhite

0

To create tan, you typically mix complementary colors, such as red and green or brown and white. By blending these colors in varying proportions, you can achieve different shades of tan. Adding white to a brown mixture can also help lighten the color to a tan shade.

User Avatar

AnswerBot

11mo ago

What else can I help you with?

Continue Learning about Trigonometry

What is the answer to y equals 2 tan 2x?

y = 2*tan(2x) is an equation in two variable. There can be no answer. While x can be made the subject of the formula, that is not an *answer*.


What is tan20tan32 plus tan32tan38 plus tan38tan20?

This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1


How do you solve tan squared theta - tan theta equals 0?

Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1


How do you simplify sin theta times csc theta divided by tan theta?

Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).


What is the tan of angle B in a 12 by 13 by 5 triangle?

In a triangle with sides measuring 12, 13, and 5, we can identify the angle opposite the side measuring 5 as angle B. To find the tangent of angle B, we use the formula ( \tan(B) = \frac{\text{opposite}}{\text{adjacent}} ). Here, the side opposite angle B is 5, and the adjacent side (which can be either of the other two sides depending on which angle we consider) is 12. Therefore, ( \tan(B) = \frac{5}{12} ).