Yes, Fe (iron) plus S (sulfur) equals FeS (iron sulfide). If the iron ion is iron(ll) then it is iron(ll) sulfide; if it is iron(lll), then it iron(lll) sulfide.
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
Fe + S = FeS
There are two elements in FeS: iron (Fe) and sulfur (S).
ordinary mixing is a physical change but when you get to heat them products are formed and it is a chemical change.
The balanced chemical equation for this reaction is: FeS + 2H⁺ → Fe²⁺ + H₂S
Fe + S ---> FeS
The reaction between iron and sulfur to form iron(II) sulfide is: Fe + S -> FeS
FeS is an ionic compound consisting of iron (Fe) cations and sulfide (S) anions. The bond between Fe and S is predominantly ionic, with Fe donating electrons to S to form ionic bonds.
To determine the mass of iron needed to react with 16.0g of sulfur, first balance the chemical equation: 8 Fe + FeS2 -> 9 FeS. As each Fe reacts with 1/2 S, the molar ratio is 8:1/2. Calculate the molar mass of Fe and FeS to convert between moles and grams. Then use the molar ratio to find the mass of Fe needed: (16.0g S)*(8 mol Fe / 1 mol S) * (55.85 g Fe / 1 mol Fe) = 711.2 g Fe.
When heated, iron filings (Fe) react with sulfur (S) to form iron sulfide (FeS). The chemical equation for this reaction is: Fe + S -> FeS.
Since it is an ionic compound, the overall charge should be zero. Iron (Fe) has possible different charges which are +2, and +3 however sulfide always has a charge of -2. Therefore, FeS is already balanced. When you write it, instead of writing "Iron Sulfide", you would write "Iron (II) Sulfide" this is because Iron has different charges and you must specify when you write it down.
FeS is not a chemical equation but a chemical formula; FeS is the chemical formula of iron sulfide.