In short no. Momentum is always conserved so you always end up with exactly the same amount you started off with.
One subtelty is that momentum is a vector quantity so direction matters. Thus if you have two balls of equal mass moving with the same speed in opposite directions their momenta are equal in magnitude (size) but oppositely directed so the total momemtum is p+(-p)=0 to start with.
A second subtelty emerges when we consider more complicated cases. If there are forces acting on the colliding bodies eg friction then we can 'lose' momentum to these forces (although really we just need to be more careful with the book-keeping).
In a collision, the total momentum of all objects before the collision is equal to the total momentum of all objects after the collision, provided no external forces are acting on the system. This is described by the principle of conservation of momentum, which states that momentum is neither created nor destroyed; it is simply transferred between objects during a collision.
The total momentum before a collision is equal to the total momentum after the collision, according to the law of conservation of momentum. This means that in a closed system, the sum of the momenta of all objects involved remains constant before and after the collision.
The quantity that remains conserved in all types of collisions is momentum. This means that the total momentum before the collision is equal to the total momentum after the collision, regardless of the type of collision taking place.
Completely If you add all the energy of all the resultants of the collision together, you will arrive at the same value as the sum of the energies of all the components before the collision.
An elastic collision is one in which both momentum and kinetic energy are conserved. In an elastic collision, the total kinetic energy before the collision is equal to the total kinetic energy after the collision. This type of collision is characterized by no energy being lost or dissipated as heat or sound.
A car driving into a very large rock. A collosion where all the things colliding (in the example the car and the rock) are no longer moving after the collision is one where all the kentic energy is lost. K.E. = 1/2 * m * v2 If v=0 then there is no kinetic energy.
In a collision between two billiard balls, momentum is conserved. This means that the total momentum of the two balls before the collision is equal to the total momentum after the collision. The momentum is transferred between the two balls during the collision, resulting in changes in their individual velocities.
The momentum stays the same.
In an elastic collision, both momentum and kinetic energy are conserved. This means that the total momentum of the system before and after the collision remains the same. In the case of two helium atoms colliding elastically, the total momentum of the atoms before the collision will be equal to the total momentum of the atoms after the collision.
The principle of conservation of momentum states that the total momentum of the system before the collision is equal to the total momentum after the collision, assuming no external forces are involved. Therefore, the total momentum of the objects involved in a collision will remain the same before and after the collision.
Negative negative, and quite false as well.Regardless of how many objects are involved, and as long as the collisions are'elastic' ... meaning that no energy is lost in crushing, squashing, pulverizing, orheating any of the objects ... the grand total of all their momenta (momentums)after the collision is exactly the same as it was before the violence erupted.
The total momentum of a system is the sum of the momenta of all the individual objects in the system. For example, in a collision between two billiard balls, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system.