The pressure that there would be if all the non-helium atoms and molecules were taken away.
To find the partial pressures of helium and oxygen in the gas tank, we can use Dalton's Law of Partial Pressures. Given that the mixture is 75% helium, the partial pressure of helium (P_He) is 75% of the total pressure: P_He = 0.75 × 20.1 ATM = 15.075 ATM. The remaining 25% is oxygen, so the partial pressure of oxygen (P_O2) is 25% of the total pressure: P_O2 = 0.25 × 20.1 ATM = 5.025 ATM.
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
The partial pressure of hydrogen gas can be calculated by subtracting the partial pressure of helium from the total pressure. Therefore, the partial pressure of hydrogen gas would be 161 mm Hg (600 mm Hg - 439 mm Hg = 161 mm Hg).
The total pressure inside the tank is the sum of the partial pressures of the gases present. In this case, Total pressure = partial pressure of oxygen + partial pressure of helium = 10 atm + 32.8 atm = 42.8 atm.
42.8 atm fufurjthfhhudjd
To find the partial pressure of oxygen, you can subtract the partial pressures of helium and carbon dioxide from the total pressure of 1 atmosphere (760 mm Hg). Partial pressure of oxygen = Total pressure - Partial pressure of helium - Partial pressure of carbon dioxide = 760 mm Hg - 609.5 mm Hg - 0.5 mm Hg = 150 mm Hg.
The initial total pressure is 1.0 ATM + 2.0 ATM = 3.0 ATM. Therefore, 6.0 ATM - 3.0 ATM = 3.0 ATM of helium was added to the tank. Hence, the partial pressure of helium in the tank is 3.0 ATM.
To find the mole fraction of CH4, we first need to calculate the total pressure of the mixture. Total pressure = partial pressure of CH4 + partial pressure of He = 0.72 ATM + 0.22 ATM = 0.94 ATM. Then, we use the formula for mole fraction: Mole fraction of CH4 = (partial pressure of CH4) / (total pressure). Mole fraction of CH4 = 0.72 ATM / 0.94 ATM ≈ 0.766.
Industrial deep-sea divers must breathe a mixture of helium and oxygen to prevent a disorienting condition known as nitrogen narcosis. If a diver's tank is filled with a helium-oxygen mixture to a pressure of 170 atmospheres and the partial pressure of helium is 110 atmospheres, the partial pressure of the oxygen is ? - is the question The answer is 60. Total pressure minus the partial pressure= 170-110= 60.
The question seems to be asking about the amount of helium in a liter of gas. One liter of gas is a volume measurement, and it can contain different amounts of helium depending on the mixture. If you're asking about pure helium, one liter will contain one liter of helium gas at standard temperature and pressure. If it's a mixture, the helium content would be specified as a percentage or in terms of partial pressure.
yes helium does have a lot of pressure.
1.6 ATM