In Halo 3's map "The Pit," players cannot normally get past the fence due to the game's collision detection and map boundaries. However, there are some glitches and exploits that players have discovered, allowing them to temporarily bypass certain barriers. These methods are not part of standard gameplay and can vary in effectiveness. It's generally recommended to enjoy the map as designed for the best experience.
boucain
To my understanding Sometime during mid to late january.
no if you want to unlock it you have to finish the vidmaster acheivments p.s. there is only 7 vidmaster acheivments but its HARD
3s + 1
135=3s +15 120=3s 40=s
28 3s
3S Facility simply means sales, services and spares
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
Halo: Reach was the last game made by Bungie and was released on September 14, 2010. In it the setting will be on Planet Reach, a planet inhabited by humans. You play as Noble Six in Noble Team which is a group of Spartan 3s and one Spartan 2. The events take place in the Fall of Reach, about 20 years before Halo: CE. Microsoft will be making the new Halo games but they're probably just going to screw up the fun. -.- It's not 20 years before CE! It's less than a month before the events of Halo CE. The Pillar of Autumn escapes Reach and after carrying out the Cole Protocol finds Halo and Keyes decides to land on it. Read your books, and play your games. the guy who wrote the second awnser is right. the order of the games should be; halo reach- halo 1- halo 2- halo 3 & halo 3 ODST.
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
4 3s = 4*3 = 12, which is a rational number.
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)