What is 12t3-48t?

Answer 1

The expression (12t^3 - 48t) can be factored by taking out the greatest common factor, which is (12t). This gives us (12t(t^2 - 4)). Further factoring (t^2 - 4) using the difference of squares results in (12t(t - 2)(t + 2)). Thus, the completely factored form is (12t(t - 2)(t + 2)).