The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
2KF -> 2K + F2
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
The reaction between potassium and fluorine results in the formation of potassium fluoride (KF), a white crystalline salt. The chemical equation for this reaction is: 2K + F2 → 2KF. This is a highly exothermic reaction due to the high reactivity of both elements.
The balanced equation for the reaction is: 2KF + Cl2 -> 2KCl + F2
The balanced symbol equation between fluorine and potassium chloride is: 2KF + Cl2 -> 2KCl + F2
Potassium bromide and fluorine would react to form potassium fluoride and bromine gas. The balanced chemical equation for this reaction is 2KBr + F2 -> 2KF + Br2.
The double replacement reaction between potassium fluoride and hydrobromic acid would result in the formation of potassium bromide and hydrofluoric acid. The balanced chemical equation for this reaction is: 2KF + 2HBr → 2KBr + 2HF.
Does this mean: How does potassium (capital K, solid reactive metal) react with hydrogen fluoride (capitals HF, weak but reactive acid when in water solution)) then the answer is in the next reaction equation: 2K + 2HF --> 2KF + H2 Products are: KF potassium fluoride, H2 gas, very explosive with air.
When hydrofluoric acid (HF) reacts with potassium hydroxide (KOH), they undergo a neutralization reaction to form potassium fluoride (KF) and water (H2O). The balanced chemical equation for this reaction is: 2HF + 2KOH -> 2KF + 2H2O. This reaction also releases heat due to the exothermic nature of the neutralization process.
The balanced chemical equation for the reaction is 2KI + F2 --> 2KF + I2. From the equation, 1 mol of F2 produces 1 mol of I2. Therefore, 0.72 mol of F2 will produce 0.72 mol of I2. The molar mass of iodine (I2) is approximately 253.8 g/mol, so 0.72 mol of I2 is equal to 0.72 mol * 253.8 g/mol ≈ 183 g of iodine produced.
The molar mass of K is 39.10 g/mol and F is 19.00 g/mol. Calculate the moles of each reactant using their given masses, then determine the limiting reactant. In this case, K is the limiting reactant, so all K will react. If 4.00 g of K reacts, it will form the same amount (4.00 g) of KF because the stoichiometry is 2:2.